25c^2-90c+81=0

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Solution for 25c^2-90c+81=0 equation:


Simplifying
25c2 + -90c + 81 = 0

Reorder the terms:
81 + -90c + 25c2 = 0

Solving
81 + -90c + 25c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(9 + -5c)(9 + -5c) = 0

Subproblem 1

Set the factor '(9 + -5c)' equal to zero and attempt to solve: Simplifying 9 + -5c = 0 Solving 9 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -5c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -5c = 0 + -9 -5c = 0 + -9 Combine like terms: 0 + -9 = -9 -5c = -9 Divide each side by '-5'. c = 1.8 Simplifying c = 1.8

Subproblem 2

Set the factor '(9 + -5c)' equal to zero and attempt to solve: Simplifying 9 + -5c = 0 Solving 9 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -5c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -5c = 0 + -9 -5c = 0 + -9 Combine like terms: 0 + -9 = -9 -5c = -9 Divide each side by '-5'. c = 1.8 Simplifying c = 1.8

Solution

c = {1.8, 1.8}

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